3^x^2=(1/9)^x-4

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Solution for 3^x^2=(1/9)^x-4 equation: 



3^x^2=(1/9)^x-4

We move all terms to the left:

3^x^2-((1/9)^x-4)=0



Domain of the equation: 9)^x-4)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3^x^2-((+1/9)^x-4)=0

We multiply all the terms by the denominator


3^x^2*9)^x-4)-((+1=0

Wy multiply elements

27x^2+1=0

a = 27; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·27·1
Δ = -108
Delta is less than zero, so there is no solution for the equation

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